Question

Point C ∈ AB, AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.

Answer 1

We are given that

point C lies on AB

Let's assume AC=x

we know that

CB=AB-AC

`CB=30-x`

Point C is 1.5 times farther from point A than from point B

so, we get

`(AC)/(CB) =1.5`

now, we can plug values

`(x)/(30-x) =1.5`

now, we can solve for x

`x=1.5\left(30-x\right)`

`x=18`

so, we get

`AC=18`

now, we can find CB

`CB=30-18`

`CB=12`

so, we get

`AC=18`

`CB=12`...............Answer