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Point C ∈ AB, AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.

User Brienna
by
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1 Answer

3 votes

We are given that

point C lies on AB

Let's assume AC=x

we know that

CB=AB-AC


CB=30-x

Point C is 1.5 times farther from point A than from point B

so, we get


(AC)/(CB) =1.5

now, we can plug values


(x)/(30-x) =1.5

now, we can solve for x


x=1.5\left(30-x\right)


x=18

so, we get


AC=18

now, we can find CB


CB=30-18


CB=12

so, we get


AC=18


CB=12...............Answer

User Whats Canasta
by
8.0k points

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