Question

Please Help <3 Please Help <3

Answer 1

Hey, there! For this question, we can just start by plugging in the known values.
`(f + g)(x)` can be rewritten as
`((x)/(2) - 3 + 3x^2 + x - 6)(x)`.

Combine like terms:
`((x)/(2) + x - 3 - 6 + 3x^2)(x)`

If you add x to
`(x)/(2)`, x will become
`(2x)/(2)`, which means that x/2 + x = 3/2x.

-->
`((3)/(2)x - 9 + 3x^2)(x)`

If you rearrange this, then your answer will be option b. Hope this helps.

Answer 2

f(x) =
`(x)/(2)` - 3

+ g(x) = 3x² + x - 6

f(x) + g(x) = 3x² +
`(x)/(2)` + x -3 - 6

= 3x² +
`(3)/(2)x` - 9

Answer: B