Answer:
Option B. 0.6 seconds
Explanation:
As given in the table at time t = 0 the maximum height of the penny is 2 meters.
In simpler way we can say the penny has been throw from a height of 2 meters.
Now this process can be represented by the equation of motion
![h=ut+(1)/(2)gt^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/dz4vui5lxmerafkz4gt754bf69l5fhqhbg.png)
For free fall u = 0
So
![h=(1)/(2)gt^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/pd9yw15n9rq9im8g9g22igm9xf97toy54u.png)
where h = 2 meters
and g = 9.81 m/sec²
By putting these values in the equation
![2=(1)/(2)(9.81)(t)^(2)=4.905t^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/o6ggetrqofxiished8z9s6f85ulg91b01p.png)
![t^(2)=(2)/(4.905)=0.4077](https://img.qammunity.org/2019/formulas/mathematics/high-school/ehdd07rp09ktaxyac9odpri40yva95m2uw.png)
t = √0.4077 = 0.6385 seconds
or t = 0.6 seconds
Answer is option B. 0.6 seconds