Question

A quadratic function has a line of symmetry at x=-3.5 and zero at -9 what is the distance from the given zero to line of symmetry

Answer 1

5.5

Explanation:

Answer 2

If a quadratic function has zero at x=-9, then point (-9,0) lies on the graph of quadratic function.

A line of symmetry has equation x=-3.5 that is x+3.5=0.

Use formula for the distance from point
`(x_0,y_0)` to the line AX+By+C=0:

`d=(|Ax_0+By_0+C|)/(√(A^2+B^2)).`

Thus,

`d=(|-9+3.5|)/(√(1^2+0^2))=5.5.`

Answer: the distance is 5.5 units.