Given:MO−→− bisects ∠LMNm∠LMO = 6x−20m∠NMO = 2x+36Solve for x and find m∠LMN.

QAmmunity.org

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Oct 17, 2019 15.3k views

3 votes

Given:MO−→− bisects ∠LMNm∠LMO = 6x−20m∠NMO = 2x+36Solve for x and find m∠LMN.

Mathematics
middle-school

Milos Gregor asked

by Milos Gregor

8.3k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

7 votes

X=14

Plug it back into both angles add it together and LMN = 128 degrees

Psmears answered Oct 21, 2019

by Psmears

7.9k points

0 Comments

Please log in or register to add a comment.

← Prev Question Next Question →

Related questions

asked Feb 23, 2021 189k views

6/5(8k+2)=-36solve equation

Stefan Nobis asked Feb 23, 2021

by Stefan Nobis

8.8k points

Mathematics
college

2 answers

3 votes

189k views

asked Nov 9, 2024 175k views

MO bisects ZLMN, m∠LMN = (7x - 24), and m∠ZNMO = (2x + 31). Solve for x and find m∠LMO, m∠ZOMN, and m∠LMN. A) x = 10, m∠LMO = 13°, m∠ZOMN = 51°, m∠LMN = 42° B) x = 14, m∠LMO = 12°, m∠ZOMN = 53°, m∠LMN

Dimitris Maf asked Nov 9, 2024

by Dimitris Maf

8.5k points

Chemistry
high-school

3 answers

3 votes

175k views

asked Jan 17, 2024 127k views

m∠LMN=m∠NMO m, angle, N, M, O, equals, one half, left bracket, m, angle, L, M, N, right bracket\text{m}\angle NMO=\frac{1}{2}\left(\text{m}\angle LMN\right)m∠NMO= 2 1 (m∠LMN) m, angle, L, M, N, equals,

Kalanamith asked Jan 17, 2024

by Kalanamith

8.6k points

Mathematics
high-school

1 answer

0 votes

127k views

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Related questions

Other Questions