Question

Factor the expression over the complex numbers.

x^2+52

Answer 1

Here we are given the expression:

`x^(2)+52`

Now let us equate it to zero to find x first,

`x^(2)+52=0`

Now subtracting 52 from the other side,

`x^(2)=-52`

taking square root on both sides,

So we will get two values of x as ,

`x=+2√(-13)`

`x=-2√(-13)`

Now we can write square root -1 as i,

So our factors become,

`x=+2i√(13)`

`x=-2i√(13)`

Answer:

The final factored form becomes,

`(x+2i√(13))(x-2i√(13))`