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PLEAS I REALLY NEED HELP!! TRIGONOMETRIC RATIOS IN RIGHT TRIANGLES

PLEAS I REALLY NEED HELP!! TRIGONOMETRIC RATIOS IN RIGHT TRIANGLES-example-1
PLEAS I REALLY NEED HELP!! TRIGONOMETRIC RATIOS IN RIGHT TRIANGLES-example-1
PLEAS I REALLY NEED HELP!! TRIGONOMETRIC RATIOS IN RIGHT TRIANGLES-example-2
User Altia
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sin x = opposite side / hypotenuse (the hypotenuse is the longest side ) so sin A in the given triangle = 5 / 13

cos x = adjacent side / hypotenuse. The adjacent side to angle A is AC so cos A = AC / 13

tan x = opposite side / adjacent side In the diagram tan A = 5 / AC

csc x = 1 / sin x = H / O ( H=hypotenuse and O = opposite) side

sec x = 1 / cos x = H/ A ( A = adjacent side)

cot x = 1 / tanx = A / O

In the triangle AC^2 = 13^2 - 5^2 = 144 so AC = 12 ( By Pythagoras)

User Avijit Nagare
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