Question

What is the axis of symmetry of h(x)=5x^2+40x+64

Answer 1

The axis of symmetry of a parabola is the vertical line passing through its vertex. Given a parabola
`ax^2+bx+c=0`, the vertex x-coordinate can be found using

`x = -(b)/(2a)`

In your case, the formula leads to

`x = -(40)/(10) = -4`

So, this parabola is symmetric with respect to the line
`x = -4`