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Solve for x over the complex numbers. x^2+8x+20=0

X= or X=

User Blaklaybul
by
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2 Answers

4 votes

Answer:you can use the quadratic formula but if you have to factor do the following:

x^2+8x+20=0

add -4 to both sides of the equation to complete the square

x^2+8x+20+(-4)=0+(-4)

x^2+8x+16=-4

(x+4)^2=-4

take the square root of both sides

x+4=+sqrt(-4)

x+4=+sqrt[(4)(-1)]

x+4=+2sqrt(-1) where sqrt(-1)=i, a complex number

x+4=+2i

x=-4+2i

x=-4+2i and x=-4-2i

you would get the same answer using the quadratic formula

Explanation:

User Oleg Abrazhaev
by
8.0k points
5 votes

Steps:


x=(-8+√(8^2-4\cdot \:1\cdot \:20))/(2\cdot \:1): -4+2i


x=(-8-√(8^2-4\cdot \:1\cdot \:20))/(2\cdot \:1) -4-2i

=\frac{-8-\sqrt{16}i}{2\cdot \:1}
=-8-√(16)i


=(-8-√(16)i)/(2)


=(-8-4i)/(2)


=-2\left(2+i\right)


=-4-2i


x=-4+2i,\:x=-4-2i

User Minding
by
7.6k points

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