Question

PLEASE HELP WILL GIVE THANKS AND FIVE STARS IF RIGHT ANSWER

Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y plus five squared divided by nine = 1.

Answer 1

(x+4)^2 / 9 - (y+3)^2 / 16 = 1

a^2 = 16 and b^2 = 9

a = +4 and -4

b = +3 and -3

Center is (-4, -3)

Vertices is (-4 + a, -3) and (-4 - a, -3)

Vertices is (-1, -3) and (-7, -3)