Question

A gas with constant temperature has a pressure of 4 atm this pressure changes to 0.2 atm causing the volume to increase to 500L what was the initial volume of the gas

Answer 1

Using the combined gas law of P1V1=P2V2 and plug it in you get (4)V1 for you don't have initial volume = (0.2)(500) --> 4V1=100, divide by the coefficient on both sides and you get V1=25

Answer 2

`25L`

Step-by-step explanation:

The problem can be solved using Boyle's law for the volume and pressure of a gas at constant temperature:

`P_(1)V_(1)=P_(2)V_(2)`

Where the quantities with sub-index 1 are the initial conditions for the gas and the quantities with sub-index 2 are for the final conditions of the gas.

We want to know the initial volume, this is:

`V_(1)=(P_(2)V_(2))/(P_(1))`

we also know from the problem that

`P_(1)=4atm\\P_(2)=0.2atm\\V_(2)=500L`

Thus, the initial volume V1 is:

`V_(1)=(0.2atm*500L)/(4atm)`

`V_(1)=25L`