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1 vote
Solve
(b-2ya^2)(3b-3ya^2)

User Max Fahl
by
5.1k points

2 Answers

3 votes

Answer:

The answer is 3b² - 9bya² - 6y²a².

Step-by-step explanation:

(b - 2ya²)(3b-3ya²)

3b² - 3bya²-6bya²-6ya²

3b² - 9bya² - 6y²a².

Answer would be 3b² - 9bya² - 6y²a².

User Sunsay
by
6.2k points
4 votes

Here we are given the expression:


(b-2ya^(2))(3b-3ya^(2))

We will use foil method to solve this expression.

The word FOIL is an acronym for the four terms of the product:

First ("first" terms of each binomial are multiplied together)

Outer ("outside" terms are multiplied—that is, the first term of the first binomial and the second term of the second)

Inner ("inside" terms are multiplied—second term of the first binomial and first term of the second)

Last ("last" terms of each binomial are multiplied)

Using this method let us simplify our expression.


(b-2ya^(2))(3b-3ya^(2))

=
3b^(2)-3bya^(2)-6bya^(2)+6y^(2)a^(4)

Now combining like terms we have:

=
3b^(2)-9bya^(2)+6y^(2)a^(4)

Answer:
(b-2ya^(2))(3b-3ya^(2)) simplifies to
3b^(2)-9bya^(2)+6y^(2)a^(4)


User Gaurang Sondagar
by
5.3k points