1 Answer

Moiz Farooq · Answer 1 · 2019-12-13T00:16:25+0000

If you plug in the x and y values for the points (X,Y).
Then you are able to solve for the equation by seeing whether or not it equals the Y value.
Ex. Solving 9a.
Step One Equation and Point (2,0) or (X,Y)

$y = ({x})^(2) - 3(x) + 2$
Step 2 Plug in and solve

$0 = {2}^(2) - 3(2) + 2$
0=4-6+2

0=0

Done and Answer is Yes it does fit.

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