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4 votes
Luiza runs a lawn-mowing business she decides to measure the rate at which the volume of fuel she uses increases with the area of the lawn what can be an appropiate unit for luiza's purpose

User Kchan
by
6.7k points

2 Answers

1 vote

Answer:

L/KM^2

Explanation:

User Kanwal
by
6.5k points
3 votes

Answer:


(Gallons)/(Feet^(2) )

Explanation:

We have been told that Luiza runs a lawn-mowing business she decides to measure the rate at which the volume of fuel she uses increases with the area of the lawn and we are asked to determine an appropriate unit for Luiza's purpose.

Since we can represent rate of units as
(Dependent Variable)/(Independent Variable)

We can see that in this case dependent variable is amount of fuel used in lawn-mowing and area of lawn is independent variable.

We know that we can represent volume of fuel as gallons and area of lawn as square feet.

Therefore, appropriate unit for Luiza's purpose is
(Gallons)/(Feet^(2) ).

User Thebiglife
by
5.6k points
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