Question

What is the square root of 28x to the third power y to the third power

Answer 1

Hello!

√28x³y³ is equal to
`2xy√(7xy)`

We can find this solution through the following steps.

1. Rewriting the equation by factoring 4 from 28, factoring out x², and factoring out y²
2. We then can rewrite 4 as 2² in our equation, leaving us with
   `\sqrt{2^(2)*7*(x^(2)x)*y^(2)y }`
3. We will then move our x and 7, and rewrite
   `2^(2)*x^(2)* y^(2)` as
   `(2xy)^(2)`
4. We can then pull the terms from the radical leaving us with
   `2xy√(7xy)`