Question

A 5.0-kg box is given a brief push and travels 5.0 m up a plane that makes an angle of 30.0 A 5.00 x 10° N crate is at the top of a 5.00 m ramp. which is inclined at 20.0° with the horizontal.

What is its potential energy? (g- 9.81 m/s?)
855 J
c. 815 J
b. 2350J
d. 8390 J

Answer 1

555

Step-by-step explanation:

L = .5a(t2)

8 = .5a(42)

8 = .5a(16)

8 = 8a

1m/s = a

F l l = 49(sin(30))

F l l = 24.5N FNET = F p - F l l - F f k And then newtons law: F p - F l l - F f k = m(a) F p - 24.5 - 21.22 = 5(1) F p = 50.72N