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If f(1)=2 and f(n)=f(n-1)-5 , then what is f(6)

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f(n) = f(n - 1) - 5

f(1) = 2

f(2) = f(2 - 1) - 5 = 2 - 5 = -3

f(3) = f(3 - 1) - 5 = f(2) - 5 = -3 - 5 = -8

f(4) = f(4 - 1) - 5 = f(3) - 5 = -8 - 5 = -13

f(5) = f(5 - 1) - 5 = f(4) - 5 = -13 - 5 = -18

f(6) = f(6 - 1) - 5 = f(5) - 5 = -18 - 5 = -23

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