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What mass of carbon dioxide is produced from the complete combustion of 6.40*10^-3 g of methane

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Answer:-
1.76*10^-^2 g of carbon dioxide.

Solution:- The balanced equation for the combustion of methane is:


CH_4+2O_2\rightarrow CO_2+2H_2O

There is 1:1 mol ratio between methane and carbon dioxide. Grams of methane are converted to moles and then using mol ratio we get the moles of carbon dioxide that could further be converted to grams. The calculations are shown as:


6.40*10^-^3gCH_4((1molCH_4)/(16gCH_4))((1molCO_2)/(1molCH_4))((44gCO_2)/(1molCO_2))

=
1.76*10^-^2gCO_2

So, complete combustion of given amount of methane gives
1.76*10^-^2gCO_2 .

User Shailesh Mishra
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