Question

An object is moving at a velocity of 23 m/s. It accelerates to a velocity of 85 m/s over a time of 8.3 s. What acceleration did it experience?

Answer 1

`(v \: final \: - v \: initial )/(time) = \: a`

`\\ (85 - 23)/(8.3) = 7.467 \: \frac{m}{ {s}^(2) }`

Answer 2

Answer : It experience the acceleration is,
`7.5m/s^2`

Explanation :

By the 1st equation of motion,

`v=u+at` ...........(1)

where,

v = final velocity = 85 m/s

u = initial velocity = 23 m/s

t = time = 8.3 s

a = acceleration = ?

Now put all the given values in the above equation 1, we get:

`85m/s=23m/s+a* (8.3s)`

`a=7.5m/s^2`

Thus, it experience the acceleration is,
`7.5m/s^2`