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A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the four substances whose properties are given, which is the most likely identity of this substance?

Substance Density (g/cm3) Melting Point (°C) Boiling Point (°C)
molybdenum 10.28 2,623 4,639
mercury 13.53 -39 357
hafnium 13.31 2,233 4,603
lead 11.34 327 1,749
A.
molybdenum
B.
mercury
C.
hafnium
D.
lead

User Rheeantz
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2 Answers

1 vote

Answer:

the one above me

Step-by-step explanation:

User Netlander
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5.8k points
5 votes

Answer:- C. Hafnium.

Solution:- Mass of the sample is 46.0 g and it's volume is
3.5cm^3 .

From mass and volume, we can calculate it's density using the formula:


density=(mass)/(volume)


density=(46.9g)/(3.5cm^3)


density=(13.4g)/(cm^3)

On the basis of the density, this substance could either be mercury or hafnium. Since the substance is a solid at room temperature where as mercury is liquid. So, it can't be mercury.

The right choice is C) Hafnium.

User Shawn Vader
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5.6k points