The slope intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3. What is the point slope form of the equation for this line?

Question

asked Sep 17, 2019 122k views

2 Answers

EastSw · Answer 1 · 2019-09-19T09:39:08+0000

y + 13 = 5x + 10

the equation of a line in ' point- slope form ' is

y - b = m(x - a) (m is the slope and (a, b ) a point on the line )

from y = 5x - 3 we obtain m = 5 and (a, b ) = ( - 2, - 13 )

y + 13 = 5(x + 2) in point- slope form

Desorder · Answer 2 · 2019-09-23T05:29:27+0000

Answer:
(y+13)=5(x+2)

Explanation:

The equation of a line in intercept form is given by:-

y=mx+x , where m is the slope of line .

Comparing given equation
y = 5x -3 to above equation, we get

Slope : m= 5

The point slope form of a line with slope m that passes through point (a,b) is given by :-

(y-b)=m(x-a)

Thus , the point slope form of the equation for this line with slope 5 and asses through point (-2, -13) will be :-

(y-(-13))=5(x-(-2))

(y+13)=5(x+2)