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Solve y=x^2+23 for x

User Syedelec
by
8.8k points

2 Answers

2 votes

Answer:

x = +/- (square root) y-23

Explanation:

A P E X

User Tuks
by
7.8k points
3 votes

For this case we must clear x from the given equation:


y = x ^ 2 + 23

We passed 23 subtracting the other side of equality:


y-23 = x ^ 2

By definition,
a ^ 2 = bis written as
a = +/-√(b)

So, we have:


x = + / -\sqrt{(y-23)

So, the solution of
y = x ^ 2 + 23 for x is:


x = + / -\sqrt{(y-23)

Answer:


x = + / -\sqrt{(y-23)


x1=+\sqrt{(y-23)


x2=-\sqrt{(y-23)


User Cristian Pena
by
8.5k points

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