Answer:
vertical distance, s = 0.16 meters
Step-by-step explanation:
It is given that,
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard.
Dashboard is placed at a distance of 2.7 meters.
Calculating time from velocity and distance i.e.

Using second equation of motion for finding vertical distance :

Here, u = 0 (for vertical velocity )
s = 0.162 meters
or s = 0.16 meters
Hence, the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard is 0.16 meters.