Question

What is the LCM of xy(x + 1) and x(x + 2)?

A.x2(x + 3)


B.x2(x + 1)(x + 2)


C.xy(x + 1)(x + 2)


D.xy(x + 3)

Answer 1

The answer is (C)

Step-by-step explanation

`xy (x + 1), x(x+2)`

By multiplying x in equation

`y(x^2 + x), x^2 + 2x`

`y(x^2 + x), x(x+2)`

All the 4 factors are (x^2 + x), y, x, (x + 2)

So, the LCM is

`xy(x + 1)(x + 2)`