Question

Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0% if the ball moves though the air for 3.2 seconds what’s the horizontal distance traveled by the ball

Answer 1

To find the horizontal distance traveled by the ball, we calculate the horizontal component of its initial velocity by multiplying the initial velocity by the cosine of the angle.

Step-by-step explanation:

To find the horizontal distance traveled by the ball, we need to calculate the horizontal component of its initial velocity. Since the initial velocity is given as 10.0 m/s at an angle of 30.0°, we can use trigonometry to determine the horizontal component.

The horizontal component can be found by multiplying the initial velocity by the cosine of the angle:

Horizontal component = initial velocity * cos(angle)

Plugging in the given values, we get:

Horizontal component = 10.0 m/s * cos(30.0°) = 10.0 m/s * 0.866 = 8.66 m/s

Now, we can calculate the horizontal distance traveled by multiplying the horizontal component of the initial velocity by the time the ball moves through the air:

Horizontal distance = horizontal component * time = 8.66 m/s * 3.2 s = 27.712 m

Therefore, the horizontal distance traveled by the ball is approximately 27.712 meters.