Question

Which of the following is the solution to the quadratic equation x2 + 16x + 55 = 0?

A.x = 11, -5


B.x = -11, 5


C.x = -11, -5


D.x = 11, 5

Answer 1

The answer is not found among the options A, B, C or D.

The standard form of a quadratic equation is ax² + bx + c = 0. Here, a is the coefficient of x² (which is 1 in this case), b is the coefficient of x (which is 16), and c is the constant (which is 55).

To find the roots of a quadratic equation ax² + bx + c = 0, we use the quadratic formula, which is x = [ -b ± sqrt(b²-4ac) ] / 2a.

Here, b²-4ac = (16)² - 4x1x55 = 256 - 220 = 36, which is a perfect square, so we can continue.

Then the quadratic formula gives us two solutions:

Solution1 = [ -16 + sqrt(36) ] / (2x1) = -16 + 6 / 2 = -5
Solution2 = [ -16 - sqrt(36) ] / (2x1) = -16 - 6 / 2 = -11

So, the roots of the equation are x= -5 and x= -11.

Matching our solutions with the options given, we do not find any that fits the result. Therefore, the answer is not found among the options A, B, C or D.

Answer 2

hope this helps you.....