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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line?

2x – 5y = –15


2x – 5y = –17


2x + 5y = –15


2x + 5y = –17

User Darkhorse
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8.4k points

1 Answer

2 votes

Answer: The correct option is (C)
2x+5y=-15.

Step-by-step explanation: Given that the equation of the line that passes through (-5, -1) and (10, -7) in point-slope form is given by


y+7=-(2)/(5)(x-10)~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to find the standard form of the equation for the above line.

We know that the STANDARD form of the equation of a line is given by


ax+by=c,~~~~~\textup{[a and b cannot be zero at the same time]}.

From equation (i), we have


y+7=-(2)/(5)(x-10)\\\\\Rightarrow 5(y+7)=-2(x-10)\\\\\Rightarrow 5y+35=-2x+20\\\\\Rightarrow 2x+5y=20-35\\\\\Rightarrow 2x+5y=-15.

Thus, the required standard form is
2x+5y=-15.

Option (C) is CORRECT.

User Hiren Panchal
by
8.6k points

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