Question

The rate constant for the first-order decomposition of n2o is 3.40 s-1. what is the half-life of the decomposition?

a. 0.491 s
b. 0.204 s
c. 0.236 s
d. 0.424 s
e. 0.294 s

Answer 1

Hey There:

First order half life equation :

T 1/2 = ln ( 2 ) /K

T 1/2 = 0.693 / 3.40

T 1/2 = 0.204 s

Answer B

Answer 2

Answer: The half life of the decomposition reaction is 0.204 s

Step-by-step explanation:

The equation used to calculate half life for first order kinetics:

`t_(1/2)=(0.693)/(k)`

where,

k = rate constant of the reaction =
`3.40s^(-1)`

`t_(1/2)` = half life of the reaction = ?

Putting values in above equation, we get:

`t_(1/2)=(0.693)/(3.40s^(-1))\\\\t_(1/2)=0.204s`

Hence, the half life of the decomposition reaction is 0.204 s