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Write the equation of line in slope-intercept form. Line parallel to y=−2x+3 that passes through the point (−100,−100)

User Chmod
by
7.8k points

2 Answers

5 votes

Answer:

y = - 2x - 100

Explanation:

Remark


The line we want is a line parallel to y = - 2x + 3


That means it has the same slope as the given line. The given line has a slope of -2


y = -2x + b is what you have so far. Now you have to use the point to get b


y = - 100


x = - 100


Solve for b


-100 = -2(-100) + b


-100 = 200 + b Notice the sign change. Two minus's make a plus. Subtract 200 from both sides.


- 100 - 200 = b


- 300 = b


Answer


y = - 2x - 100



User Yushatak
by
7.8k points
0 votes

When you want a parallel line through a given point (h, k), you can start with the equation you have and do the following:

  • eliminate the constant term
  • replace x with (x-h)
  • replace y with (y-k)

Here, that looks like

... (y-(-100)) = -2(x-(-100))

... y = -2x -200 -100 . . . . . eliminate parentheses, add -100

... y = -2x -300 . . . . the equation you want.

User Yu Zhou
by
8.3k points
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