Calm Down this is a nasty proof
CB is parallel to ED (Given)
CB is congruent to ED (Given)
Angle CBF is congruent to Angle EDF (Vertical Angles)
Angle DEF is congruent to Angle BCF (Alternate Interior Angles)
Angle EDF is congruent to Angle CBF (Alternate Interior Angles)
Therefore we now have enough information to solve. We have a side angle side triangle here so.....
Triangle CBF is congruent to Triangle EDF because of the Side Angle Side Theorem.
Good Luck and Your Welcome