Question

What is the area of rectangle ABCD with vertices A -3,0 B 3,2 C 4,-1 D -2,-3

Answer 1

For this, simply find the width and length by finding the distance between the two points. This can be done using the equation
`√((y2 - y1)^2 + (x2 - x1)^2)`

AB(length):
`√((0 - 2)^2 + (3 - (-3))^2)`

-->
`√(-2^2 + 6^2)`

--->
`√(40)` = 6.32

BC(width):
`\sqrt{(2 - (-1))^2 + (4 - 3)^2`

-->
`√((2 + 1)^2 + 1^2)`

--->
`√(27 + 1)`

---->
`√(28)` = 5.29 ≈ 5.3

Area = 33.496 ≈ 33.5