Question

A 5.0-kg block of wood is placed on a 2.0-kg aluminum frying pan. How much heat is required to raise the temperature of both the wood and the pan from 20°C to 45°C? (Note: The specific heat wood is 1700 J/kg ·°C and of aluminum is 900 J/kg ·°C.)

Answer 1

Heat required to raise the temperature of a given system is

`Q = ms\Delta T`

here we know that

m = mass

s = specific heat capacity

`\Delta T` = change in temperature

now as we know that

mass of wood = 5 kg

mass of aluminium pan = 2 kg

change in temperature = 45 - 20 = 25 degree C

specific heat capacity of wood = 1700 J/kg C

specific heat capacity of aluminium = 900 J/kg C

now here we will find the total heat to raise the temperature of both

`Q = m_1s_1\Delta T_1 + m_2s_2\Delta T_2`

`Q = 5 * 1700 * 25 + 2 * 900 * 25`

`Q = 212500 + 45000`

`Q = 257500 J`

So heat required to raise the temperature of the system is 257500 J