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What is the inverse of g(x)=(x-1)/4? is it g-1(x)=4x+1?
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What is the inverse of g(x)=(x-1)/4? is it g-1(x)=4x+1?

User Jeto
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g(x)=(x-1)/(4)\to y=(x-1)/(4)\\\\\text{change x to y and y to x}\\\\x=(y-1)/(4)\ \ \ \ |\text{solve for y}\\\\(y-1)/(4)=x\ \ \ \ \ |\cdot4\\\\y-1=4x\ \ \ \ |+1\\\\y=4x+1\\\\\boxed{g^(-1)(x)=4x+1}

User David Xia
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