Question

Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through the system is (5.772 - 5.323i) milliamperes (mA). The impedance (Z) in that same system is (3.342 + 4.176i) kilohms (kΩ). Please tell me the magnitude of the voltage in the circuit.

Answer 1

41.99 or 42.0 volts.

Explanation:

We have been given the impedance (Z) of the circuit which is:

`Z=3.342+4.176i`

and the current through the circuit is:

`(5.772-5.323i)`

The voltage across the circuit is given by:

`V= I* Z=IZ`, where 'V' is the voltage, 'I' is the current, and 'Z' is the impedance.

Plugging the values of 'I' and 'Z' we get:

`V=(5.772-5.323i)* 10^(-3)* (3.342+4.176i)* 10^3`

`V=(5.772-5.323i)*(3.342+4.176i)`

`V= (41.51+6.31i)`

Now that we have the voltage, we can find the magnitude of the voltage as follows:

`V= √((41.51)^2+(6.31)^2)=√(1723.08+39.81)=√(1762.89)=41.98 \approx 42.0`

So the magnitude of the voltage across the circuit is 42.0 Volts.