Question

Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through the system is (5.772 - 5.323i) milliamperes (mA). The impedance (Z) in that same system is (3.342 + 4.176i) kilohms (kΩ). Please tell me the magnitude of the voltage in the circuit.

Answer 1

Answer:Magnitude of voltage is 41.9963 volts

Explanation:

Given that current I =5.772-5.323i mA

and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

`=(5.772-5.323i)X10^(-3)X(3.342+4.176i)X10^(3)`

`V=(5.772-5.323i)X(3.342+4.176i)`

`V=19.290024+24.103872i-17.789466i-23..5148848i^(2)`

`V=41.518892+6.314406i`

Magnitude of V =
`\sqrt{41.518892^(2) +6.314406^(2) }=√(1763.6901)=41.9963volts`