Question

What is f(–3) for the function f(a) = –2a2 – 5a + 4?

Answer 1

f(-3)=f(a)
-3=a

So you need to plug -3 into all the a's


`f(a) = f( - 3) = - 2 ( - 3)^(2) - 5( - 3) + 4`

= -2(9) - (-15) + 4
= -18 + 15 + 4
= -3 + 4
= 1

Answer:

When you plug input of -3 your output will be 1

Answer 2

The value of f(-3) is 1.

Explanation:

Given expression,

`f(a)=-2a^2-5a+4----------(1)`

For finding the value of f(-3),

Put a = - 3 in equation (1),

We get,

`f(-3)=-2(-3)^2-5(-3)+4`

`=-2(9)+15+4`

`=-18+19`

`=1`

Hence, the value of f(-3) is 1 for the given function.