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What is the 33rd term of this arithmetic sequence?

12, 7, 2, -3, -8, …

User Nwayve
by
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1 Answer

5 votes

a1 = 12

common difference = -5

a(n) = a1 + d(n - 1)

a(n) = 12 - d(n-1)

so if 33rd term then

a(33) = 12 -5(32)

a(33) = 12 - 160

a(33) = -148

Answer

-148

User SquidsEnMasse
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7.6k points

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