Question

The sum of two numbers is 120. Three times

their difference is 48. What are the numbers?
TERS A.5(C) A.1(A), A1(B)
F. 16, 120
G 36, 52
H 52,68
J 68, 84
Pleasss help thank you :)

Answer 1

The answer is 68 and 52

Explanation:

x + y = 120

3(x - y ) = 48

We have 3x + 3y = 360

and 3x - 3y = 48

Adding we have the following:

6x = 408

x = 68

y = 120-48 = 52