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Human body temperatures have a mean of 98.20 degrees Fahrenheit and a standard deviation of 0.62 degrees Fahrenheit. Convert 103.00 degrees Fahrenheit to a z-score and determine if it is usual of unusual. Unusual means that the z-score is more than 2 standard deviations below or above the mean.

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Answer:

z-score will be: 7.741.... and it will be unusual.

Explanation:

Human body temperatures have a mean of 98.20 degrees Fahrenheit and a standard deviation of 0.62 degrees Fahrenheit.

So here,
\mu= 98.20 and
\sigma= 0.62

Formula for z-score is:
z= (X-\mu)/(\sigma)

Thus, the z-score for 103.00 degrees Fahrenheit will be.......


z(X=103.00)= (103.00-98.20)/(0.62)=7.741...

As, here the z-score is more than 2 standard deviations above the mean, so 103.00 degrees Fahrenheit is unusual for human body temperature.

User Duncan Ogle
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