Question

whats the velocity if a seagull drops a shell from rest at a height of 11m, how fast is the shell moving when it hits the rocks

Answer 1

Seagull is at height 11 m

it drops a shell from rest

so here we know that

acceleration of shell is due to free fall = -9.81 m/s^2

displacement = - 11 m

initial speed = 0

now we will use kinematics equation here in order to find the final speed

`v_f^2 = vi^2 + 2as`

now plug in all values in it

`v_f^2 = 0 + 2*(-9.81)*(-11)`

`v_f^2 = 215.82`

`v_f = 14.7 m/s`

so here the speed by which shell will strike with the rocks is 14.7 m/s