Question

CALCALATE the temperature change when 1000j of heat is supplied to 100g of water​

Answer 1

2.39 °C

Step-by-step explanation:

Specific heat of water = 4187 j / kg °C (You eaither have to be given this, or know this or look it up)

100 g of water = .1 kg of water

1000 j / (.1 kg * °C) = 4187 j / (kg °C)

solve for C = 2.39°C