230k views
1 vote
A worker pushes a large rock to the north while another worker helps by pushing it to the east. If they both exert equal force, in what direction does the rock move?

Question 2 options:

northeast

east

north

southwest

User SalkinD
by
7.4k points

1 Answer

7 votes

let the magnitude of force applied by each worker be "F"

consider east-west direction along X-axis and north-south direction along Y-axis

In unit vector form, force vector by worker pushing in east direction is given as


\underset{A}{\rightarrow} = F
\hat{i} + 0
\hat{j}


In unit vector form, force vector by worker pushing in north direction is given as


\underset{B}{\rightarrow} = 0
\hat{i} + F
\hat{j}

resultant force is given as the vector sum of two vector forces as


\underset{R}{\rightarrow} =
\underset{A}{\rightarrow} +
\underset{B}{\rightarrow}


\underset{R}{\rightarrow} = (F
\hat{i} + 0
\hat{j} ) + (0
\hat{i} + F
\hat{j} )


\underset{R}{\rightarrow} = F
\hat{i} + F
\hat{j}

direction of the force is hence given as

θ = tan⁻¹(F/F)

θ = tan⁻¹(1)

θ = 45 degree north of east

hence the direction is north-east


User Healing
by
7.4k points