Question

The length of rectangular field is twice its breadth.If the perimeter of the field is 228,find the dimensions of the field

Answer 1

We have the equations: l = 2b and 2l + 2b = 228;

Then, 4b + 2b = 228;

6b = 228;

b = 228/6;

b = 38 (breadth);

l = 2·38;

l = 76 (length);