Remark
Each term and the next one is separated by 4.
14 - 10 = 4
6 - 1 = 4
The common difference is 4
d = 4
General equation for this series
t_n = a + (n - 1)*d
t_n =2 + (n-1) * 4
Next 2 terms
t5 = 2 + (5 - 1)*4 substitute 5 for n
t5 = 2 + 4*4 Calculate the answer
t5 = 18
t_6
t6 = 2 + (6 -1)*4
t6 = 2 + 5*4
t6 = 22
I hope you can figure out the last one. Just look up at t5