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Graph the linear equation using intercepts

Graph the linear equation using intercepts-example-1
User Jori
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The x-intercept is when y = 0

while

The y-intercept is when x = 0

So, to find the x-intercepts, set y to 0:

3x - 5(0) = 15

3x = 15

Divide both sides by 3:

x = 5

x-intercept is (5, 0)

Now, for the y-intercept:

3(0) - 5y = 15

-5y = 15

Divide both sides by -5:

y = -3

y-intercept is (0, -3)

Therefore, the x-intercept is (5, 0), and the y-intercept is (0, -3).

Now, lets find the slope using these 2 points on the graph and the rate of change formula, which is:


(y2 - y1)/(x2 - x1)

Plug in the intercepts (the order of y's and x's doesn't really matter as long as they're consistent):


(0 + 3)/(5 - 0) =
(3)/(5)

Therefore, the slope is
(3)/(5), or rise 3, run 5.

Now, lets graph:

( hope this helps! :) )

Graph the linear equation using intercepts-example-1
User Sarosh Mirza
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