Let's assume
Marcella’s age is x
now, we are given
Justin is 2 years older than one third Marcella’s age
so, Justin's age will be
![=2+(1)/(3) x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/nnfu1m2rkpfssasan9pb6sfruzy7wt6srj.png)
Let's assume Justin's age is J
so, we get
![J=2+(1)/(3) x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/l4jyvvzali47cg4z9el8380lvf0tko3e1m.png)
Aimee is four years younger than 2times Justin’s age
so,
Aimee's age will be
![=2J-4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/xwi7he24e7y3s8h8y1l0hwz2vsa3joe669.png)
now, we can plug J
![A=2*(2+(1)/(3) x)-4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/chd08pzj5l76jsn8jd5qp80unto4mhlphe.png)
now, we are given
Marcella is 63 years old
so, x=63
we can plug x=63 and find A
![A=2*(2+(1)/(3) *63)-4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zt231wnrfed9js6txl3rqqd4qiegz2wcyo.png)
![A=42](https://img.qammunity.org/2019/formulas/mathematics/middle-school/3kigknao4osoiqqpk3jicdj2l4iv8kw8a3.png)
so,
Aimee's age is 42 years
![J=2+(1)/(3) x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/l4jyvvzali47cg4z9el8380lvf0tko3e1m.png)
now, we can plug x=63
![J=2+(1)/(3) *63](https://img.qammunity.org/2019/formulas/mathematics/middle-school/1l60gp8xfcl5haog2lxqkgji55bxxov9zf.png)
![J=23](https://img.qammunity.org/2019/formulas/mathematics/middle-school/v4bzrxxf4ehuy6z6f52hbew5ucxiot6krw.png)
so, Justin's age is 23 years