Question

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Write a quadratic function in standard form whose graph has the given characteristics.
passes through (- 8,0), (- 6, -16), and (2,0).

Answer 1

Answer:
`y=x^2 +6x-16`

Explanation:

From the roots, the equation in factored form is
`y=a(x-2)(x+8)`. Substituting in the coordinates (-6, -16),

`-16=a(-6-2)(-6+8)\\\\-16=-16a\\\\a=1`

So, the equation is
`y=(x-2)(x+8)`, which expands to
`x^2 +6x-16`.