Question

Which line is perpendicular to 5y+3y=15?

3x+ 5y= 10
10x-6y=18
Y+5=-3
Y=-3x+10

Answer 1

None of the provided equations represent a vertical line which would be perpendicular to the horizontal line represented by y = 15 / 8. Thus, none of the equations is perpendicular to the given line.

Step-by-step explanation:

To determine which line is perpendicular to the given equation, we need to understand the concept of slope. For the equation 5y + 3y = 15, simplifying it first will give us y = 15 / (5 + 3), simplifying further we get y = 15 / 8. This implies the slope is 0 since the equation is now y = constant, which is a horizontal line.

Now, looking at the provided choices:

• 3x + 5y = 10
• 10x - 6y = 18
• Y + 5 = -3
• Y = -3x + 10

The slopes of these lines, when put in slope-intercept form (y = mx + b), are as follows:

• m = -3/5 for the first equation,
• m = 10/6 for the second equation,
• m = 0 for the third equation (which is a horizontal line and thus parallel to the given line),
• m = -3 for the fourth equation.

Since a horizontal line is perpendicular to a vertical line, we look for the equation that represents a vertical line (m is undefined). Therefore, none of the provided equations are perpendicular to the given equation y = 15 / 8, since they all have defined slopes.

Answer 2

There is not a correct answer in your options. It should be a line with a slope of 3/5.

In order to find this, we first need to find the slope of the original line by solving for y.

5x + 3y = 15

3y = -5x + 15

y = -5/3x + 5

So with the slope of -5/3, we know perpendicular slope must be the opposite and a negated version of that. This would be 3/5. We can tell none of the above answer have exactly that slope. Therefore, there must be a typo in your question.