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Factor the expression over the complex numbers. x^2+18

User Hayk
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2 Answers

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x^2+18=\\\\x^2-(-18)=\\\\(x-√(-18))(x+√(-18))=\\\\(x-3\sqrt2i)(x+3\sqrt2i)

User Kevin Pilch
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8.9k points
4 votes

Answer:

The factors are
(x-3\sqrt2 i)(x+3\sqrt2 i)

Explanation:

Given : Expression
x^2+18

To find : Factor the expression over the complex numbers ?

Solution :

Expression
x^2+18

First we solve for x,


x^2+18=0


x^2=-18

Taking root both side,


x=√(-18)


x=\pm 3√(2)i

So, The factors are
(x-3\sqrt2 i)(x+3\sqrt2 i)

User Bob Walsh
by
8.9k points

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