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Is this equation x^9-5x3+6= 0 in quadratic form

User Luke Pring
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2 Answers

7 votes

Answer:

The equation is not quadratic in form.

The variable part of the first term is not the square of the variable part of the

second term.

The result of squaring x cubed is x to the 6th power, not the 9th power.

Explanation:

User DanteTheEgregore
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5.9k points
3 votes

No, it's not. A quadratic form is something like


ax^2+bx+c=0

They won't necessarily come in this exact form, but the important part is that there must be a constant term, and the other two terms must be powers of the variable, and one must be the square of the other.

In this case, for example,
x^2 is the square of
x

So, for example, an equation like


-7x^8-5x^4+18 is in quadratic form, because there is a constant term (18), and
x^8 is the square of
x^4. You can tell this because the exponents are one the double of the other.

So, in this case, you have
x^9 which is the cube of
x^3, so this equation is not in quadratic form.

User Neghez
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4.9k points